```
SELECT s.name AS '姓名', c.name AS '课程名称', s.score AS '成绩', AVG(s.score) AS '平均成绩'
FROM student s, course
2023-07-11 10:49
135.31372
17
0
0
0
Student(S#,Sname,Sage,Ssex) 学生表Course(C#,Cname,T#) 课程表SC(S#,C#,score) 成绩表Teacher(T#,Tname) 教师表问题：1、查询“001”课程
2021-12-07 14:35
131.38263
32
0
0
0